Answer
Solutions:
$x=-\frac{5}{4}+\frac{\sqrt {241}}{4}$
$x=-\frac{5}{4}-\frac{\sqrt {241}}{4}$
Work Step by Step
$-2x^2-5x+27=0~~$ ($a=-2,b=-5,c=27$):
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-(-5)±\sqrt {(-5)^2-4(-2)(27)}}{2(-2)}=\frac{5±\sqrt {241}}{-4}=-\frac{5}{4}±\frac{\sqrt {241}}{4}$
