Answer
Solutions:
$x=1+3i$
$x=1-3i$
Work Step by Step
$x^2-2x+10=0~~$ ($a=1,b=-2,c=10$):
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-(-2)±\sqrt {(-2)^2-4(1)(10)}}{2(1)}=\frac{2±\sqrt {-36}}{2}=\frac{2±6i}{2}=1±3i$
$x=1+3i$ or $x=1-3i$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - Review Exercises - Page 153: 77
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