Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 1 - 1.5 - Complex Numbers - 1.5 Exercises - Page 120: 96

Answer

See below.

Work Step by Step

$\overline{(a_1+b_1i)(a_2+b_2i)}=\overline{a_1a_2-b_1b_2+i(a_1b_2+b_1a_2)}=a_1a_2-b_1b_2-i(a_1b_2+b_1a_2)$ $\overline{(a_1+b_1i)}\cdot\overline{(a_2+b_2i)}=(a_1-b_1i)(a_2-b_2i)=a_1a_2-b_1b_2-i(a_1b_2+b_1a_2)$ These are equal, thus we proved what we had to.
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