Answer
Solutions:
$x=1+i$
$x=1-i$
Work Step by Step
$x^2-2x+2=0~~$ ($a=1,b=-2,c=2$):
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-(-2)±\sqrt {(-2)^2-4(1)(2)}}{2(1)}=\frac{2±\sqrt {-4}}{2}=\frac{2±2i}{2}=1±i$
$x=1+i$ or $x=1-i$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.5 - Complex Numbers - 1.5 Exercises - Page 120: 67
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