Answer
$2+\sqrt 2i$ or $2-\sqrt 2i$
Work Step by Step
$x^2-4x+6=0$
$(x-2)^2=-2$
x-2 = +$\sqrt 2 i$ or $-\sqrt 2 i$
x = $2+\sqrt 2 i$ or $2-\sqrt 2 i$
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