Answer
False.
Work Step by Step
$(a+bi)+(s+ti)=(a+s)+(b+t)i$
$(a+s)+(b+t)i$ is a real number if $b+t=0$, that is, if $b=-t$. But in most cases, this does not happen.
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.5 - Complex Numbers - 1.5 Exercises - Page 120: 89
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