Answer
Solutions:
$x=-3+i$
$x=-3-i$
Work Step by Step
$x^2+6x+10=0~~$ ($a=1,b=6,c=10$):
$x=\frac{-b±\sqrt {b^2-4ac}}{2a}=\frac{-6±\sqrt {6^2-4(1)(10)}}{2(1)}=\frac{-6±\sqrt {-4}}{2}=\frac{-6±2i}{2}=-3±i$
$x=-3+i$ or $x=-3-i$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.5 - Complex Numbers - 1.5 Exercises - Page 120: 68
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