Chapter 9 Quadratic Relations and Conic Sections - 9.5 Graph and Write Equations of Hyperbolas - 9.5 Exercises - Problem Solving - Page 647: 40a

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We have $a=13.3\\c=28.2$ Find b by using the formula: $c^2=a^2+b^2\\b^2=c^2-a^2$ Plug in the given values: $b^2=(28.2)^2-(13.3)^2\\b=\sqrt 618.35$ The standard form for a horizontal transverse hyperbola is: $$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\frac{x^2}{(13.3)^2}-\frac{y^2}{(28.2)^2}=1\\\frac{x^2}{176.89}-\frac{y^2}{618.35}=1$$