Answer
See below
Work Step by Step
From part b, we know $$\frac{x^2}{930.25}-\frac{y^2}{236.451}=1$$
Rewrite as: $$\frac{x^2}{930.25}-1=\frac{y^2}{236.451}\\
y^2=\frac{236.451x^2}{930.25}-236.451$$
Thus: $$y=\sqrt \frac{236.451x^2}{930.25}-236.451$$
We know the x-coordinate is $42$.
Substitute and solve for y: $y=\sqrt \frac{236.451(42)^2}{930.25}-236.451\approx14.56$
Since this is the vertical distance from the horizontal line at $0$, we find:
$h=14.56+40=54.56$ ft
