Chapter 9 Quadratic Relations and Conic Sections - 9.5 Graph and Write Equations of Hyperbolas - 9.5 Exercises - Problem Solving - Page 647: 40b

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We have $a=4.1\\c=25$ Find b by using the formula: $c^2=a^2+b^2\\b^2=c^2-a^2$ Plug in the given values: $b^2=(25)^2-(4.1)^2\\b=608.19$ The standard form for a horizontal transverse hyperbola is: $$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\frac{x^2}{(4.1)^2}-\frac{y^2}{(608.19)^2}=1\\\frac{x^2}{16.81}-\frac{y^2}{608.19}=1$$