Answer
See below
Work Step by Step
We can see that $a=\frac{\sqrt 2}{2}\\c=\frac{\sqrt 3}{2}$
Find b by using the formula: $c^2=a^2+b^2\\b^2=c^2-a^2$
Plug in the given values: $b^2=(\frac{\sqrt 3}{2})^2-(\frac{\sqrt 2}{2})^2\\b=\frac{1}{2}$
The standard form for a horizontal transverse hyperbola is:
$$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\frac{x^2}{(\frac{\sqrt 2}{2})^2}-\frac{y^2}{(\frac{1}{2})^2}=1\\\frac{x^2}{0.5}-\frac{y^2}{0.25}=1$$