Answer
$x=5$
Work Step by Step
According to the exercise our equation is: $2x(x-1)(x-4)=40\\x(x-1)(x-4)=20\\x(x^2-5x+4)=20\\x^3-5x^2+4x-20=0\\(x-5)(x^2+4)$
Thus $x^2+4=0$ (but this is impossible since $x^2$ is non-negative) or $x-5=0\\x=5$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 5 Polynomials and Polynomial Functions - 5.4 Factor and Solve Polynomial Equations - 5.4 Exercises - Skill Practice - Page 357: 52
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