Answer
$w=\pm1$
Work Step by Step
$4w^4+40w^2-44=4(w^4+10w^2-11)=4(w^2+11)(w^2-1)=0$
Thus $w^2+11=0$ (but this is impossible since $w^2$ is non-negative or $w^2-1=0\\w^2=1\\w=\pm1$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 5 Polynomials and Polynomial Functions - 5.4 Factor and Solve Polynomial Equations - 5.4 Exercises - Skill Practice - Page 357: 36
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