Answer
Option C
Work Step by Step
Solving the equation by factoring and setting the factors equal to zero, we find:
$$3x^4-x^3-27x^2+9x=0 \\ x\left(3x-1\right)\left(x+3\right)\left(x-3\right)=0 \\ x=0,\:x=\frac{1}{3},\:x=-3,\:x=3$$
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