Answer
$$g=-3,\:g=-1,\:g=1$$
Work Step by Step
Solving the equation by factoring and setting the factors equal to zero, we find:
$$g^3+3g^2-g-3=0 \\ \left(g+3\right)\left(g+1\right)\left(g-1\right)=0 \\ g=-3,\:g=-1,\:g=1$$
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