Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 5 Polynomials and Polynomial Functions - 5.4 Factor and Solve Polynomial Equations - 5.4 Exercises - Skill Practice - Page 357: 38

Answer

$b=-3$

Work Step by Step

The equation is the same as: $5b^3+15b^2+12b+36=(b+3)(5b^2+12)=0$ Thus $5b^2+12=0$ (but this is impossible since $b^2$ is non-negative) or $b+3=0\\b=-3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.