Answer
$y=-\frac{1}{4}(x+3)^{2}+3$
Work Step by Step
We already know $y$, $x$, $k$ and $h$ from the given vertex and point, so in order to get the quadratic function we need to find $a$...
$y=a(x-h)^{2}+k$
$-1=a(1+3)^{2}+3$
$-4=a(4)^{2}$
$16a=-4$
$a=-\frac{4}{16}$
$a=-\frac{1}{4}$
Therefore the function is...
$y=-\frac{1}{4}(x+3)^{2}+3$