Answer
$y=-\frac{3}{4}(x-2)^{2}+1$
Work Step by Step
We already know $y$, $x$, $k$ and $h$ from the given vertex and point, so in order to get the quadratic function we need to find $a$...
$y=a(x-h)^{2}+k$
$-2=a(4-2)^{2}+1$
$-3=a(2)^{2}$
$4a=-3$
$a=-\frac{3}{4}$
Therefore the function is...
$y=-\frac{3}{4}(x-2)^{2}+1$