Answer
$y=\frac{3}{2}(x-5)^{2}-4$
Work Step by Step
We already know $y$, $x$, $k$ and $h$ from the given vertex and point, so in order to get the quadratic function we need to find $a$...
$y=a(x-h)^{2}+k$
$20=a(1-5)^{2}-4$
$24=a(-4)^{2}$
$16a=24$
$a=\frac{24}{16}$
$a=\frac{3}{2}$
Therefore the function is...
$y=\frac{3}{2}(x-5)^{2}-4$