Chapter 4 Quadratic Functions and Factoring - 4.10 Write Quadratic Functions and Models - 4.10 Exercises - Skill Practice - Page 312: 3

$y=(x-3)^{2}+2$

We already know $y$, $x$, $k$ and $h$ from the given vertex and point, so in order to get the quadratic function we need to find $a$... $y=a(x-h)^{2}+k$ $6=a(5-3)^{2}+2$ $4=a(2)^{2}$ $4a=4$ $a=\frac{4}{4}$ $a=1$ Therefore the function is... $y=(x-3)^{2}+2$