Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.8 Use Inverse Matrices to Solve Linear Systems - 3.8 Exercises - Skill Practice - Page 215: 29

Answer

$x=10, y=-2$

Work Step by Step

Rewrite our system of equations in matrix form: $\begin{bmatrix} -2& -9\\ 4 & 16 \end{bmatrix}.\begin{bmatrix} x\\ y \end{bmatrix}=\begin{bmatrix} -2\\ 8 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\frac{1}{-32+36}\begin{bmatrix} 16 & 9\\ -4&-2 \end{bmatrix}.\begin{bmatrix} -2\\ 8 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\frac{1}{4}\begin{bmatrix} 40\\ -8 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\begin{bmatrix} 10\\ -2 \end{bmatrix}$ Hence, $x=10, y=-2$
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