Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 3 Linear Systems and Matrices - 3.8 Use Inverse Matrices to Solve Linear Systems - 3.8 Exercises - Skill Practice - Page 215: 27

Answer

$x=-1, y=-4$

Work Step by Step

Rewrite our system of equations in matrix form: $\begin{bmatrix} 3 & -2\\ 6 & -5 \end{bmatrix}.\begin{bmatrix} x\\ y \end{bmatrix}=\begin{bmatrix} 5\\ 14 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\frac{1}{-15+12}\begin{bmatrix} -5 & 2\\ -6&3 \end{bmatrix}.\begin{bmatrix} 5\\ 14 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\frac{-1}{3}\begin{bmatrix} 3\\ 12 \end{bmatrix}$ $\begin{bmatrix} x\\ y \end{bmatrix}=\begin{bmatrix} -1\\ -4 \end{bmatrix}$ Hence, $x=-1, y=-4$
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