Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.5 Apply the Law of Sines - 13.5 Exercises - Skill Practice - Page 886: 28

Answer

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Work Step by Step

The sum of the angles of the triangle is $180^\circ$ $$A+B+C=180^\circ\\B=180^\circ-A-C\\B=180^\circ-32^\circ-67^\circ\\B=81^\circ$$ Use the law of sines: $$\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{y\sin C}$$ First we obtain: $\frac{c}{\sin C}=\frac{b}{\sin B}\\c=\frac{b}{\sin B}\times \sin C\\c=\frac{31}{y\sin 81^\circ}\times\sin 67^\circ \approx 28.9^\circ$ Hence, the correct answer is B.
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