Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 13, Trigonometric Ratios and Functions - 13.5 Apply the Law of Sines - 13.5 Exercises - Skill Practice - Page 886: 25

Answer

See below.

Work Step by Step

$C=180-49-32=99^\circ$. Using the law of sines, $\frac{a}{\sin49^\circ}=\frac{44}{\sin32^\circ}\\a=\frac{44\sin49^\circ}{\sin32^\circ}\approx62.67$ $\frac{c}{\sin99^\circ}=\frac{44}{\sin32^\circ}\\c=\frac{44\sin99^\circ}{\sin32^\circ}\approx82.01$
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