Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-4 Factoring to Solve Quadratic Equations - Practice and Problem-Solving Exercises - Page 558: 9

Answer

The solutions are $-1\frac{1}{4}$ and $-7$.

Work Step by Step

If a product is 0, one of the factors must be 0. Use the addition property of equality and the multiplication property of equality to solve for k. $4k+5=0\ or\ k+7=0$ $4k+5-5=0-5\ or\ k+7-7=0-7$ $4k=-5\ or\ k=-7$ $4k\div4=-5\div4\ or\ k=-7$ $k=\frac{-5}{4}\ or\ k=-7$ $k=-1\frac{1}{4}\ or\ k=-7$
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