Answer
$p=7, -3$
Work Step by Step
$p^2-4p=21$
$p^2-4p-21=21-21$
$p^2-4p-21 = 0$
$(p-7)(p+3)=0$
$p-7=0$
$p-7+7=0+7$
$p = 7$
$p+3=0$
$p+3-3 = 0-3$
$p = -3$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 9 - Quadratic Functions and Equations - 9-4 Factoring to Solve Quadratic Equations - Practice and Problem-Solving Exercises - Page 558: 21
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