Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-4 Factoring to Solve Quadratic Equations - Practice and Problem-Solving Exercises - Page 558: 17

Answer

$z=-1.5, 12$

Work Step by Step

$2z^2-21z-36=0$ $2z^2-24z+3z-36=0$ $2z(z-12)+3(z-12)=0$ $(2z+3)(z-12) = 0$ $2z+3 = 0$ $2z+3-3 =0-3$ $2z = -3$ $2z/2 = -3/2$ $z = -1.5$ $z-12 = 0$ $z-12+12 = 0+12$ $z = 12$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.