Chapter 12 - Data Analysis and Probability - 12-7 Thoretical and Experimental Probability - Practice and Problem-Solving Exercises - Page 761: 20

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P(event)=$\frac{numberoffavorableoutcomes}{numberofpossibleoutcomes}$ There are 6 possible outcomes because there are 6 total numbers. 6 is the number of favorable outcomes because all numbers are either even or odd P(event)=$\frac{numberoffavorableoutcomes}{numberofpossibleoutcomes}$ P(even or odd)=$\frac{6}{6}$ -simplify- P(even or odd)=1