Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 12 - Data Analysis and Probability - 12-7 Thoretical and Experimental Probability - Practice and Problem-Solving Exercises - Page 761: 13

Answer

$\frac{2}{3}$

Work Step by Step

Use p(not less than 3)=$\frac{numeroffavorableoutcomes}{numberofpossible outcomes}$ There are 6 possible outcomes. There are 4 favorable outcomes:3,4,5 and 6. Plug into the fraction: p(not less than3)=$\frac{favorableoutcomes}{possibleoutcomes}$ p(not less than 3)=$\frac{4}{6}$ p(not less than 3)=$\frac{2}{3}$
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