Chapter 12 - Data Analysis and Probability - 12-7 Thoretical and Experimental Probability - Practice and Problem-Solving Exercises - Page 761: 16

$\frac{5}{6}$

P(event)=$\frac{numberoffavorableoutcomes}{numberofpossibleoutcomes}$ There are 6 possible outcomes. There are 5 numbers which are not 2(1,3,4,5,6) so 5 is the number of favorable outcomes. P(event)=$\frac{numberoffavorableoutcomes}{numberofpossibleoutcomes}$ P(not 2)=$\frac{5}{6}$