Chapter 12 - Data Analysis and Probability - 12-7 Thoretical and Experimental Probability - Practice and Problem-Solving Exercises - Page 761: 15

$\frac{1}{2}$

P(event)=$\frac{numberoffavorableoutcomes}{numberofpossibleoutcomes}$ There are 6 possible outcomes. There are 3 even numbers(2,4,6) so 3 is the number of favorable outcomes. P(event)=$\frac{numberoffavorableoutcomes}{numberofpossibleoutcomes}$ P(even numbers)=$\frac{3}{6}$ -simplify- P(even numbers)=$\frac{1}{2}$