Chapter 12 - Data Analysis and Probability - 12-7 Thoretical and Experimental Probability - Practice and Problem-Solving Exercises - Page 761: 19

$\frac{2}{3}$

P(event)=$\frac{numberoffavorableoutcomes}{numberofpossibleoutcomes}$ There are 6 possible outcomes because there are 6 total areas. There are 4 areas which are not red so 4 is the number of favorable outcomes. P(event)=$\frac{numberoffavorableoutcomes}{numberofpossibleoutcomes}$ P(areas not red)=$\frac{4}{6}$ -simplify- P(areas not red)=$\frac{2}{3}$