Answer
$3y^2+5y+\frac{29}{3}+\frac{{124}}{{3}{(3y-5)}}$
Work Step by Step
Re-arranging the order of the terms and leaving space for missing terms, the given is equivalent to
$$
(9y^3+0y^2+4y-7)÷(3y-5)
.$$
Using the long division method shown below, then
$$\begin{aligned}
&
(9y^3+4y-7)÷(3y-5)
\\&=
3y^2+5y+\frac{29}{3}+\frac{\color{red}{124}}{\color{red}{3}\color{blue}{(3y-5)}}
.\end{aligned}
$$
