Answer
$a-1+\frac{1}{4a+7}$
Work Step by Step
Re-arranging the order of the terms, the given is equivalent to
$$
(4a^2+3a-6)÷(4a+7)
.$$
Using the long division method shown below, then
$$\begin{aligned}
&(4a^2+3a-6)÷(4a+7)
\\&=
a-1+\frac{1}{4a+7}
.\end{aligned}
$$
