Answer
$3c^2+2c - \frac{1}{3}$
Work Step by Step
$(9c^4+6c^3-c^2) \div 3c^2$ = $\frac{9c^4}{3c^2} + \frac{6c^3}{3c^2} - \frac{c^2}{3c^2}$ = $3c^2+2c - \frac{1}{3}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 11 - Rational Expressions and Functions - 11-3 Dividing Polynomials - Practice and Problem-Solving Exercises - Page 669: 10
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