Answer
$3x^2-\frac{5x}{2}+3$
Work Step by Step
$(6x^4 - 5x^3 + 6x^2) \div 2x^2$ = $\frac{6x^4}{2x^2} - \frac{5x^3}{2x^2} + \frac{6x^2}{2x^2} $ = $3x^2-\frac{5x}{2}+3$
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