Answer
$4-\frac{16}{q}$
Work Step by Step
$(8q^2 - 32q) \div 2q^2$ = $\frac{8q^2}{2q^2} - \frac{32q}{2q^2}$= $4-\frac{16}{q}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 11 - Rational Expressions and Functions - 11-3 Dividing Polynomials - Practice and Problem-Solving Exercises - Page 669: 12
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
