Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - 10-2 Simplifying Radicals - Practice and Problem-Solving Exercises - Page 610: 37

Answer

$\frac{7}{4} \sqrt 3$

Work Step by Step

$7 \sqrt \frac{6}{32}$ $\frac{6}{32}$ can be simplified to $\frac{3}{16}$ $7 \sqrt \frac{3}{16}$ We can rewrite it as $7 \frac{\sqrt 3}{\sqrt 16}$ Square root of 16 is 4 because 4 x 4 = 16 $\frac{7}{4} \sqrt 3$
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