Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 531: 21

Answer

$(4y^{2}-3)(3y+1)$

Work Step by Step

$12y^{3}+4y^{2}-9y-3=$ ...factor out the GCF of each group of two terms. $=4y^{2}(3y+1)-3(3y+1)$ ...factor out the common factor, $3y+1$. $=(4y^{2}-3)(3y+1)$
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