Answer
$(7z^{2}+8)(2z-5)$
Work Step by Step
$14z^{3}-35z^{2}+16z-40=$
...factor out the GCF of each group of two terms.
$=7z^{2}(2z-5)+8(2z-5)$
...factor out the common factor, $2z-5$.
$=(7z^{2}+8)(2z-5)$
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