Answer
$(3k^{2}-10)(4k-9)$
Work Step by Step
$12k^{3}-27k^{2}-40k+90=$
...factor out the GCF of each group of two terms.
$=3k^{2}(4k-9)-10(4k-9)$
...factor out the common factor, $4k-9$.
$=(3k^{2}-10)(4k-9)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 531: 18
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