Answer
$(2y^2+1)(7y+4)$
Work Step by Step
$14y^3+8y^2+7y+4$
Factor out the GCF of each group of two terms.
$=7y(2y^2+1)+4(2y^2+1)$
Factor out the common factor, $(2y^2+1)$
$=(2y^2+1)(7y+4)$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 531: 14
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