Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - 8-8 Factoring by Grouping - Practice and Problem-Solving Exercises - Page 531: 12

Answer

$3p^{2}$ , $1$

Work Step by Step

$6p^{3}+3p^{2}+2p+1 $ ...the first two terms: $6p^{3}=2\cdot(3\cdot p\cdot p)\cdot p$ $3p^{2}=(3\cdot p\cdot p)$ GCF:$ 3p^{2}$ ...the last two terms. $2p=1\cdot 2\cdot p$ $1=1$ GCF:$ 1$
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