Chapter 7 - Exponents and Exponential Functions - 7-2 Multiplying Powers With the Same Base - Practice and Problem-Solving Exercises - Page 431: 62

The terms are: Third is 18 Seventh is 34 Tenth is 46

To solve this, a) n=3 as third term A(3) = 10 + (3-1)(4) = 10 + (2)(4) = 10 + 8 =18 b) n=7 as seventh term A(7) = 10 + (7-1)(4) = 10 + (6)(4) = 10 + 24 =34 c) n=10 as tenth term A(10) = 10 + (10-1)(4) = 10 + (9)(4) = 10 + 36 =46