Chapter 7 - Exponents and Exponential Functions - 7-2 Multiplying Powers With the Same Base - Practice and Problem-Solving Exercises - Page 431: 49

The answer is $3^{\frac{5}{2}}$$\times$$2^{y+x}$

To solve this =$3^{\frac{1}{2}}$$\times$$2^{y}$$\times$$3^{2}$$\times$$2^{x}$. --> same base add all exponents = $3^{(\frac{1}{2}+2)}$$\times$$2^{(y+x)}$ = $3^{(\frac{1}{2}+\frac{4}{2})}$$\times$$2^{(y+x)}$ = $3^{\frac{5}{2}}$$\times$$2^{(y+x)}$