Answer
The expression would be $\frac{1}{(a+b)}$
Work Step by Step
To solve
= $(a+b)^{2}$$(a+b)^{-3}$ --> Since they have the same base, we can add the exponents.
= $(a+b)^{2+(-3)}$
= $(a+b)^{(2-3)}$
= $(a+b)^{(-1)}$
= $\frac{1}{(a+b)}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - 7-2 Multiplying Powers With the Same Base - Practice and Problem-Solving Exercises - Page 431: 50
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