Answer
The answer is $2^{2n+3}$
Work Step by Step
To solve this
= $2^{n}$$\times$$2^{n+2}$$\times$$2^{1}$. --> same base add all exponents
= $2^{(n+(n+2)+(1))}$
= $2^{(n+n+2+1)}$
= $2^{2n+3}$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 7 - Exponents and Exponential Functions - 7-2 Multiplying Powers With the Same Base - Practice and Problem-Solving Exercises - Page 431: 48
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