Answer
$x^{2}+6x+8$
Work Step by Step
Given : $\frac{x^{2}-4}{x+3} \times \frac{x^{2}+7x+12}{x-2}= \frac{(x+2)(x-2)}{(x+3)} \times \frac{(x+4)(x+3)}{(x-2)}$
$= (x+2)(x+4)=x^{2}+6x+8$
(After dividing out the common factors (x-2) and (x+3))
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - Mid-Chapter Quiz - Page 690: 9
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