Answer
$\frac{2x^{2}+17x-45}{(x-5)(x+4)}$
Work Step by Step
Given : $\frac{2x}{x-5} + \frac{9}{x+4}=\frac{2x(x+4)+9(x-5)}{(x-5)(x+4)}$
(Finding the least common denominator)
This becomes : $\frac{2x^{2}+8x+9x-45}{(x-5)(x+4)}=\frac{2x^{2}+17x-45}{(x-5)(x+4)}$
