Answer
$\frac{1}{(k+4)}, with$ $k\ne-4,k\ne2$
Work Step by Step
Given : $\frac{k-2}{k^{2}+2k-8}$
This becomes : $\frac{k-2}{(k+4)(k-2)}$
(Factor the denominator)
$=\frac{1}{(k+4)}$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.